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phy 231
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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when dealing with gravitation, i know F=GMm/R^2. I know PE=GMm/R and I also know that KE= GMm/2r. I found PE by taking the force multiplied by the distance and i found KE by setting the force equal to F=ma, in which ma is m(v^2/R), so solving for v, then plugging that back into .5mv^2, i get my above answer.
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my question is i've noticed that integrating the gravitational force gives me -PE...is there something significant about that?
@& Absolutely.
`dPE is equal and opposite to the work done by gravity.
The work done by gravity between two points is found by integrating the gravitational force with respect to position.
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