sequence notation again

MTH 163

Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Find the first 4 terms of the sequence defined by a(n) = a(n-1) + -3/n, a(0) = -3.

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This is a similar equation like the one I sent you earlier. Thanks for your help.

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Is there an easier way, I remember doing these types of equations earlier and I kinda had a hard time with them then. I'm just trying to get prepared for the test. Thanks Billy

a(n) = a(n-1) - 3/n means that

a(1) = a(0) - 3/1

a(2) = a(1) - 3/2

a(3) = a(2) - 3/3

etc.

a(1) = a(0) - 3/1 = -3 - 3/1 = -3 - 3 = -6. So a(1) = -6.

a(2) = a(1) - 3/2 = -6 - 3/2 = -7/2. So a(2) = -7/2.

a(3) = a(2) - 3/3 = -7/2 - 3/3 = -9/2. SO a(3) = -9/2

etc..

Let me know if this, along with my response to your preceding question, don't clarify the notation and its application.