course PHY 121
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released. •What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
2*5=10
2*6=12
###This should be 6 kg * 9.8 m/s^2 = 59N and 5 kg * 9.8 m/s^2 = 49 Newtons to get the weight then 59N-49N=10N and 10N/11kg=.9m/s^2
answer/question/discussion:
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
5*1.8=9
5*9=45
###This should be.9m/s^2*1s=.9m/s then -1.8m/s + .9m/s = -.9m/s
answer/question/discussion:
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
Same direction and slows down.
###The acceleration is positive and the velocity is negative which means it would be in opposite directions not the same direction but it is slowing down
&#Good work. Let me know if you have questions. &#