course PHY 121
A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball. •What is the weight of the ball?
400g / 2.5N=160g
###This would be weight = .4kg * 9.8m/s^2 =3.92N
answer/question/discussion:
• What is the buoyant force on the ball?
400g * 2.5N=1000g
###This is 2.5N – 3.92N +F_buoy = 0
F_buoy=1.42N
answer/question/discussion:
• What therefore must be its volume?
1000g +160g=1160g
###V*9800N/m^3=1.42N
V=1.42N / 9800N/m^3 = .000145m^3 which is also .145 liters or 145cm/^3
answer/question/discussion:
• What is its density?
1000g-160g=840g
###this is density=mass/volume=400g / 145cm^3 = 2.8g/cm^3 or 2800kg/m^3
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