Revised seed 271

course PHY 121

A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball. •What is the weight of the ball?

400g / 2.5N=160g

###This would be weight = .4kg * 9.8m/s^2 =3.92N

answer/question/discussion:

• What is the buoyant force on the ball?

400g * 2.5N=1000g

###This is 2.5N – 3.92N +F_buoy = 0

F_buoy=1.42N

answer/question/discussion:

• What therefore must be its volume?

1000g +160g=1160g

###V*9800N/m^3=1.42N

V=1.42N / 9800N/m^3 = .000145m^3 which is also .145 liters or 145cm/^3

answer/question/discussion:

• What is its density?

1000g-160g=840g

###this is density=mass/volume=400g / 145cm^3 = 2.8g/cm^3 or 2800kg/m^3

"

&#Let me know if you have questions. &#