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Mth 174
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Question Form_labelMessages **
Integral of Fraction Question
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integral of sin(3x) / (1 + cos(4x))
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I'm confused about what to substitute as u. I tried u = cos(x), du = -sin(x), so -3du = sin(3x). Then I tried -3 integral du/(1 + u). From there, I wasn't sure how to get the 4 inside the cos(x) to equal cos(4x).
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@&
I don't think it is possible to do that integration.
Where did you find that problem? If it was in my materials I need to fix it.
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