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Phy 121
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_01.1_labelMessages **
The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on an interval is
•average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure to identify the quantity A, the quantity B and the requested average rate.
•If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate of change in position with respect to clock time = change in position / change in clock time.
Therefore the average rate of change is (20 cm - 10 cm) / (9 seconds - 4 seconds) = 10 cm / 5 seconds = 2 cm/second
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•If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate of change in velocity with respect to clock time = change in velocity / change in clock time.
Thereforethe average rate of change is (40 cm / second - 10 cm / second) / 3 seconds = 30 / 3 = 10 cm / second / second = 10 cm / second.
I'm not sure if I am right on the unit change on the very last step.
@&
Good try, but:
(cm/sec) / sec can be written cm/sec/sec.
However it also means
(cm/sec) * (1 / sec), which is equal to cm/sec^2.
*@
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•If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
average rate at which position change with respect to clock time = change in postion / change in clock time.
Since the average rate is given, we alter the formula to Change in postion = average rate * change in clock time.
The answer would then be 5 cm / second * 10 seconds = 50 cm
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•You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I will be sure to review this exercise. One way to remember it would be to always look at the first thing listed before with respect to, that will always go on top of the equation, and the following that it has respect to will be the bottom.
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•You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
You take the phrase average rate of change of A with respect to B. A components will always go on the top of the division and B components will be found on the bottom of the division.
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30 minutes
&#Good responses. See my notes and let me know if you have questions. &#