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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
•How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m * a = 12 kg * 3 m/s^2 = 36 Newtons
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•What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = Fnet / m = 20 Newtons / 4 kg = 20 kg * m/s^2 / 4 kg = 5 m/s^2
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•If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Because if there were no other forces, you would get an acceleration of a = 20 Newtons / 10 kg = 20 kg * m/s^2 / 10 kg = 2 m/s^2, but since the acceleration was given at 1.5 m/s^2, there must be other forces at work.
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•What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = 10 kg * 1.5 m/s^2 = 15 Newtons total
This total act would be 20 Newtons in the direction of my force, and 5 in the opposite direction of my force.
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20 minutes
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