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Phy 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
•What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
The magnitude = sqrt(a^2 + b^2) = sqrt(2^2 + 3^2) = sqrt(13) = 3.6 Newtons
THe angle it makes is tan^-1 (3 / 2) = 56.3 degrees counterclockwise
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•What are the components of the equilibrant force?
The x component = -2 Newtons and the y component = -3 Newtons
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•What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
tan^-1 = (-3 / -2) = 56.3 degrees
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Very good responses. Let me know if you have questions.