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Phy 121
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_25.1_labelMessages.txt **
A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
•What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
centripetal a = v^2 / r = (30 cm/s)^2 / 20 cm = 900 cm^2/s^2 / 20 cm = 45 cm/s^2
The magnitude would be 45 cm/s^2 which converts to 0.45 m/s^2 where the direction will be toward the center.
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•What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> :
The centripetal force = m * centripetal acceleration = 0.11 kg * 0.45 m/s^2 = 0.0495 Newtons
Therefore the magnitude is equal to 0.0495 Newtons and its direction is toward the center of the circle.
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&#Good responses. Let me know if you have questions. &#