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course Mth 279
Section 2.2*********************************************
Question: 1. Solve the following equations with the given initial conditions:
1. y ' - 2 y = 0, y(1) - 3
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
y=c/(e^2t)
since y(1)=3
c=3e^2
y=(3e^2)/(e^2t)"
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