course PHY 231 I see that the Laboratory assignments are not mandatory. I was quite pleased to become aware of that.
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23:23:55 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> First the mean of a set of numbers is calulated. Then, the deviation of each number from that mean. Each deviation is then squared. The average of those squared deviations are then taken by dividing their sum by one less number than the total deviations, unless there are more than 30. The square root of this value is the standard deviation. confidence assessment: 3
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23:34:54 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> The process of fitting a straight line to a graph of y v. x data consists of find a line with the least average deviation from the actual values. Two different people would get different results if they just eyeballed the line they thought fits best. confidence assessment: 3
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23:36:14 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity equals distance over time. Rate equals distance over time. Velocity equals Rate. confidence assessment: 3
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23:36:35 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> OK self critique assessment: 3
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23:37:53 Given average speed and time interval how do you find distance moved?
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RESPONSE --> Speed multiplied by the time interval cancels the units of time and leaves distance. confidence assessment: 3
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23:38:01 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> OK self critique assessment: 3
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23:41:48 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Average speed divided by distance equals time. confidence assessment: 3
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23:42:17 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> OK, I had it backwards... self critique assessment: 3
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23:44:36 Given time interval and distance moved how do you get average speed?
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RESPONSE --> Average speed, e.g., miles / hour is distance divided by time. confidence assessment: 3
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23:44:44 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> OK self critique assessment: 3
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