course I am under the impression there is no asst 4 if this is incorrect please let me know.
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20:21:19 query R.3.16 \ 12 (was R.3.6) What is the hypotenuse of a right triangle with legs 14 and 48 and how did you get your result?
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RESPONSE --> c^2=a^2+b^2 c^2=14^2+48^2 c^=196+2304 c^2=2500 c=50
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20:21:36 ** The Pythagorean Theorem tells us that c^2 = a^2 + b^2, where a and b are the legs and c the hypotenuse. Substituting 14 and 48 for a and b we get c^2 = 14^2 + 48^2, so that c^2 = 196 + 2304 or c^2 = 2500. This tells us that c = + sqrt(2500) or -sqrt(2500). Since the length of a side can't be negative we conclude that c = +sqrt(2500) = 50. **
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RESPONSE --> ok
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20:24:29 query R.3.22 \ 18 (was R.3.12). Is a triangle with legs of 10, 24 and 26 a right triangle, and how did you arrive at your answer?
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RESPONSE --> yes, c^2=a^2+b^2 26^2=10^2+24^2 676=100+576 676=676
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20:24:38 ** Using the Pythagorean Theorem we have c^2 = a^2 + b^2, if and only if the triangle is a right triangle. Substituting we get 26^2 = 10^2 + 24^2, or 676 = 100 + 576 so that 676 = 676 This confirms that the Pythagorean Theorem applies and we have a right triangle. **
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RESPONSE --> ok
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20:28:07 query R.3.34 \ 30 (was R.3.24). What are the volume and surface area of a sphere with radius 3 meters, and how did you obtain your result?
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RESPONSE --> v=4/3pi r^3 v= 4/3pi 3^3 v=113.10^3 s=4pi r^2 s=4pi 3^2 s=113.10^2
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20:37:44 ** To find the volume and surface are a sphere we use the given formulas: Volume = 4/3 * pi * r^3 V = 4/3 * pi * 3^3 V = 4/3 * pi * 27 V = 36pi m^3 Surface Area = 4 * pi * r^2 S = 4 * pi * 3^2 S = 4 * pi * 9 S = 36pi m^2. **
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RESPONSE --> I dont understand at all how the answer is 36.
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20:40:34 query R.3.50 \ 42 (was R.3.36). A pool of diameter 20 ft is enclosed by a deck of width 3 feet. What is the area of the deck and how did you obtain this result?
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RESPONSE --> a=pi r ^2 pool area= a=pi 10^2 a=314.16 total pool and deck area= a=pi 13^2 a=530.93 total area - pool area = deck area 530.93 - 314.16= 216.77
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20:43:08 ** The deck plus the pool gives you a circle of radius 10 ft + 3 ft = 13 ft. The area of the deck plus the pool is therefore pi * (13 ft)^2 = 169 pi ft^2. So the area of the deck must be deck area = area of deck and pool - area of pool = 169 pi ft^2 - 100 pi ft^2 = 69 pi ft^2. **
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RESPONSE --> am I breaking the solution down to far?
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20:43:25 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> All ok
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20:43:37