Phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Our times start at 5 seconds and ends at 13 seconds. We have a difference of 8 seconds. Half of that is 4 seconds and 4 seconds + 5 seconds equal 9 seconds. This is our midpoint clock time.
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• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Our velocity started at 16 cm/s and ended at 40 cm/s. We have a difference of 24 cm/s. Half of that is 12 cm/s and this added to our starting point is 28cm/s. Our midpoint is going to be at 28 cm/s
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• How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Our average velocity is 28cm/s. I found this by adding our starting velocity to our ending velocity and dividing by 2. So in 8 seconds we should travel 224 cms
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• By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
8 seconds
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• By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
24 cm/sec
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• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
24 cm/sec / 8 seconds = 3cm/sec
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• What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Rise would be our change in Y or Velocity. So our rise is 24
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• What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Our run is the change in X(Time) which is 8
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• What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Our slope is rise/run. 24 /8 3. Or slope is 3.
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• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This tells us that the object velocity is increasing.
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• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The object changes a total 24 cm/sec over 8 seconds. vAve = `ds/`dt. 24cm/sec / 8 seconds equals 3cm/sec average change in velocity.
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30 Minutes
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&#Very good responses. Let me know if you have questions. &#