Phy 201
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
Our velocity is changing 8cm/s^2 each second for 3 seconds. 8cm/s^2 * 3 seconds gives us 24cm/s. This added to our starting velocity gives us an ending velocity of 36cm/s
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Since we know that our ending velocity is 36cm/s and our starting velocity is 12cm/s then to find our average we subtract our starting velocity from our ending velocity and divide by 2. We then add this to our starting velocity to get our average velocity of 24cm/s over the three second period.
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
If we are averaging 24cm/s over the 3 second period then we just multiply the 24cm/s * 3 s to get a distance of 72cm.
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20 Minutes
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&#Very good work. Let me know if you have questions. &#