Phy 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
First we must calculate our acceleration for both instances. Our first instance will have an average velocity of 10m/8s = 1.25m/s. This gives us an average acceleration of (1.25m/s)/8s = 0.156m/s^2.
ave accel is change in vel / change in clock time, not ave vel / change in clock time
Our second instance has a average velocity of 10m/5s = 2m/s. This gives us an average acceleration of (2m/s)/5s = .4m/s^2.
So we have a change of acceleration of 0.244m/s^2 over a change of .05 slope gives us a change of 4.88m/s^2 for each change of slope.
#$&*
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15 Minutes
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I am unsure if I stated the right units for my answer.
Very good, but your calculation of acceleration (ave rate of change of accel with respect to clock time) missed a very important detail.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#