Phy 201
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> : vf = v0 + a*`dt. v0 = 25m/s and a = -10m/s^2. vf= 25m/s + -10m/s^2 * 1s. At the end of one second our velocity will decrease a total of 10m/s, so our velocity at that point would be 15m/s.
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• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> : At the end of two seconds we have decrease a total of 20m/s so our velocity at that point would be 5m/s
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• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> : Our v0 is 25m/s and our vf is 5 m/s. We know that our average velocity is (vf – v0)/2, so we get -10m/s as our average velocity.
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• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> : 20 meters.
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> : At the end of an addition second we would have a velocity change of -30m/s. So our velocity at the end of 3 seconds is -5m/s. Then at an additional second we have a change of another -10m/s so we have a velocity of -15m/s at the end of 4 seconds.
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> : The ball will reach the maximum height at 2.5 seconds and will be 25 meters high.
it will be somewhat higher than that
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> : After 4 seconds we have a change in velocity of -40m/s. Our starting velocity was 25m/s and we reached our high point of 25 meters in 2.5 seconds. From that point we decreased -15m/s so our height at this point is going to be 10m/s.
10 m/s isn't a height
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• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> : At this point the ball will have passed the point that it had started. According to how high the ball was off the ground when it started will determine if the ball is on the ground at this point. The ball will be 10m below its starting point or an height of -10m if we reference its starting point as point zero.
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45 Minutes
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Then please compare your solutions with the expanded discussion at the link
Solution
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