Phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m * a
Fnet = 12kg * 3m/s^2
Fnet = 36 kg * m/s^2 = 36 Newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = Fnet/m
a = 20 kg * m/s^2/4kg
a = 5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Because using our formula a = Fnet/m gives us an acceleration of 2m/s^2 and we are only accelerating at 1.5m/s^2.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> : Since we should have an acceleration of 2m/s^2 and we only have 1.5 m/s^2 then we know that we have a force acting in the opposite way decreasing our acceleration by .5m/s^2. The total force is .5m/s^2 * 10kg = 5 Newtons in the opposite direction.
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10 Minutes
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&#Very good responses. Let me know if you have questions. &#