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Phy 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I’m not sure, but I think to find the clock time at the midpoint you would just subtract the two clock times.
13 sec - 5 sec
= 8 sec is the clock time at the midpoint of this interval.
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@& The midpoint between, say, 50 and 58 is not 58 - 50 = 8. The midpoint is 54.
How was this calculated?
How does this apply to the given question, and what is the resulting answer?*@
• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
To get this answer, I believe you just used the two velocities given, and subtract, to get the midpoint velocity.
40 cm/sec - 16 cm/ sec = 24 cm/sec
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@& This is the change in the velocity, not the midpoint velocity. See my preceding note.*@
• How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
So I take the time of the midpoint and the velocity that I found.
vAve= ‘ds/ ‘dt
vAve * ‘dt = ‘ds
24 cm/sec * 8 sec = ‘ds
192 cm would be the distance traveled during this interval
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@& It would be reasonable to use the midpoint velocity as the average velocity for the interval. However you need to find the correct midpoint velocity, which is fairly close to 24 cm/s, but is not 24 cm/s.
The midpoint clock time is not relevant to the displacement. The clock could for example have been started 10 seconds earlier, which would not afftect how long the interval lasted.
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Since the slope is positive then the graph will have a positive increasing incline. The graph starts at zero-zero and ends at 30, 5. As time increases so does position.
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*#&!
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
*@