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Phy 201
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
Average acceleration = change in v / change in time
8 cm/s^2 * 6 s = 48 cm/s
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
aAve = ‘ds/ ‘dt
= (48 cm/s - 12 cm/s) / 6s - 3 s
=( 36 cm/s) / 3 sec
= 12 cm/s per sec
@& Good
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
12 cm/s per sec then in 3 sec it will move 36 cm/s
@& You've multiplied the rate of change of velocity with respect to clock time by the change in clock time, with gives you the change in velocity. Change in velocity is not an answer to the question of 'how far'.
How would you answer the question 'how far'?*@
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