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course Phy 201
Resending quiz 2
Reason out the quantities v0, vf, `dv, vAve, a, `ds and `dt: If an object’s velocity changes at a uniform rate from 11 cm/s to 15 cm/s as it travels 117 cm, then what is the average acceleration of the object? Using the equations which govern uniformly accelerated motion determine vf, v0, a, `ds and `dt for an object which accelerates through a distance of 117 cm, starting from velocity 11 cm/s and accelerating at .444 cm/s/s.
Average Velocity : (11 cm/s + 15 cm/s) / 2
= 13 cm/s
Change in time:
117 cm / 13 cm/s
= 9 s
Average Accleration = ‘dv / ‘dt
(4 cm/s )/ 9 s
= 4/9 cm/s^2
vf = 15 cm / sec (given)
v0 = 11 cm / sec (given)
a = .444 cm/s^2 (given)
‘ds = 117 cm (given)
‘dt = 9 sec (found)
Self-critique (if necessary):
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Self-critique rating:
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@& Good.
However you need to also answer the second question:
Using the equations which govern uniformly accelerated motion determine vf, v0, a, `ds and `dt for an object which accelerates through a distance of 117 cm, starting from velocity 11 cm/s and accelerating at .444 cm/s/s. *@