Phy 121
Your 'cq_1_9.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
What are its average velocity, final velocity and acceleration?
answer/question/discussion: vAve = `ds/`dt = 20cm/2s = 10cm/s, vf = 2*vAve = 2*10cm/s, aAve = `dv/`dt = 20cm/s / 2s = 10cm/s^2
If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: vAve = `ds/`dt = 20cm/2.06s = 9.71cm/s, vf = vAve*2 = 9.71cm/s *2 = 19.42cm/s, aAve = `dv/`dt = 19.42cm/s / 2.06s = 9.42cm/s^2
What is the percent error in each?
answer/question/discussion: for vf 19.42/20 = 3 for aAve 9.71/10 = 3
If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: the percent error is the same for velocity and acceleration, `dt is directly related to each quantity, so with the slight increase in time, the velocity and acceleration both decrease at the same rate
If the percent errors are different explain why it must be so.
answer/question/discussion: they are the same
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22min
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Phy 121
Your 'cq_1_9.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
What are its average velocity, final velocity and acceleration?
answer/question/discussion: vAve = `ds/`dt = 20cm/2s = 10cm/s, vf = 2*vAve = 2*10cm/s, aAve = `dv/`dt = 20cm/s / 2s = 10cm/s^2
If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: vAve = `ds/`dt = 20cm/2.06s = 9.71cm/s, vf = vAve*2 = 9.71cm/s *2 = 19.42cm/s, aAve = `dv/`dt = 19.42cm/s / 2.06s = 9.42cm/s^2
What is the percent error in each?
answer/question/discussion: for vf 19.42/20 = 3 for aAve 9.71/10 = 3
If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: the percent error is the same for velocity and acceleration, `dt is directly related to each quantity, so with the slight increase in time, the velocity and acceleration both decrease at the same rate
If the percent errors are different explain why it must be so.
answer/question/discussion: they are the same
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22min
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Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#