course Phy 121
Your work on this assignment is good.
Let me know if anything is unclear, and include specifics about what you do and do not understand.
when the bracket was tilted back with the pearl resting on the bracket then the rhythm is closer together, when the bracket is tilted forward the rhythm is farther apart and when the bracket is level, the rhythm seems to be pretty steady.my 11 trials resulted in a 2.5 count 6 times and a 3 count 5 times. I believe the ball took the same amount of time each time because the conditions were all the same, there were no alterations. I tried to keep the same steady pace of counting each time , but it's very possible that that wasn't the case, so my counting could've vey well been inac
the avereage time was 2.73
the median time was 3
I think the mean time gives me a better idea because it is not a random choice. it's all the times averaged out.
the T=.2*sqrt(2.5)
This is T = sqrt(L), where L is length in cm. I suspect your pendulum length was more than 2.5 cm. Perhaps 2.5 inches, which would be about 6.3 cm?
T=.2*(1.58)
T=.316
It took about 2 sec for the ball to roll down the incline, i figured this by timing the counts ofthe pendulum. the counts equaled to about 2 sec. and I don't know how to answer the othr questions in that set
I think that there is a possibility that my results aren't fully accurate, it is very possible that my guess could be .1 sec off, I know it wasn't to much more than that because it didn't take much longer than that to roll down the incline
I think if the pendulum would've been longer my results would be more accurate because the rhythm would've been longer and farther apart, an easier to count. thfact that the string was short and that the pearl doesn't continue swinging and stops afterashort period of time, both limit thhe accuracy.The length of the string makes it easier to count the longer it is and harder the shorter it is, because of the speed of the swing. Again, I think the best length would be alonger length around 5-6 in."