Assignment 9 

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course Mth 163

Question: `q001. Note that this assignment has 2 questions

For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2? What therefore is the rise between these two points, and what is the run? What is the average slope of the graph between these two points? Be sure to simplify your result. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: When x= x1 we get y= 1.1(x1) + .8 Y= 1.1x1 + .8 (x1, 1.1x1+.8) when x=x2 we get y= 1.1(x2) + .8 y=1.1x2+.8 (x2, 1.1x2+.8) The rise is (1.1x2+.8) - (1.1x1 + .8) = 1.1x2 - 1.1x1 The run is x2 - x1 = x2-x1 The slope 1.1x2 - 1.1x1 / x2-x1 = 1.1(x2-x1) / x2-x1 = 1.1 confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution: In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8). The rise between the two points is therefore rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1. The run is run = x2 - x1. The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): ------------------------------------------------ Self-critique rating:

********************************************* Question: `q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2? What therefore is the rise between these two points, and what is the run? What is the average slope of the graph between these two points? Be sure to simplify your result. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: When x=x1 we get y= 3.4(x1) + 7 Y= 3.4x1 + 7 (x1, 3.4x1 + 7) When x= x2 we get y= 3.4(x2) + 7 Y= 3.4x2 + 7 (x2, 3.4x2+7) The rise is (3.4x2 + 7) - ( 3.4x1+7) = 3.4x2 - 3.4x1 The run is x2- x1 The slope is 3.4x2-3.4x1 / x2-x1 = 3.4(x2-x1) / x2-x1 = 3.4 confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution: In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7). The rise between the two points is therefore rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1. The run is run = x2 - x1. The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): ------------------------------------------------ Self-critique rating:

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Self-critique (if necessary): ------------------------------------------------ Self-critique rating:

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Self-critique (if necessary): ------------------------------------------------ Self-critique rating: #*&!

`gr31

Assignment 9 

#$&*

course Mth 163

Question: `q001. Note that this assignment has 2 questions

For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

When x= x1 we get y= 1.1(x1) + .8

Y= 1.1x1 + .8

(x1, 1.1x1+.8)

when x=x2 we get y= 1.1(x2) + .8

y=1.1x2+.8

(x2, 1.1x2+.8)

The rise is (1.1x2+.8) - (1.1x1 + .8) = 1.1x2 - 1.1x1

The run is x2 - x1 = x2-x1

The slope 1.1x2 - 1.1x1 / x2-x1 = 1.1(x2-x1) / x2-x1 = 1.1

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution:

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8).

The rise between the two points is therefore

rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1.

The run is

run = x2 - x1.

The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1.

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?

What therefore is the rise between these two points, and what is the run?

What is the average slope of the graph between these two points? Be sure to simplify your result.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

When x=x1 we get y= 3.4(x1) + 7

Y= 3.4x1 + 7

(x1, 3.4x1 + 7)

When x= x2 we get y= 3.4(x2) + 7

Y= 3.4x2 + 7

(x2, 3.4x2+7)

The rise is (3.4x2 + 7) - ( 3.4x1+7) = 3.4x2 - 3.4x1

The run is x2- x1

The slope is 3.4x2-3.4x1 / x2-x1 = 3.4(x2-x1) / x2-x1 = 3.4

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7).

The rise between the two points is therefore

rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1.

The run is

run = x2 - x1.

The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4.

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Self-critique (if necessary):

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Self-critique rating:

"

Self-critique (if necessary):

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Self-critique rating:

"

Self-critique (if necessary):

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Self-critique rating:

#*&!

&#Good work. Let me know if you have questions. &#