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course PHY 241

Sketch a velocity vs. clock time graph for an object whose initial velocity is 7 m/s and whose velocity 11 seconds later is 21 m/s. Explain what the slope of the graph

means and why, and also what the area means and why.

a = `dv / `dt = (21 - 7) / 11 = 1.3 m/s^2

`ds = vAve * `dt = ((21+7)/2) * 11 = 154 m

The slope of the graph is the acceleration of 1.3, and it represents the change of velocity with respect to time, being that m = rise / run = `dv / `dt = a.

The area under the graph is the total distance travelled. The area is a trapezoid, so A = .5b(h_1 + h_2) = .5(11)(28) = 154 = `ds."

&#Very good responses. Let me know if you have questions. &#