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PHY 241
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.2_labelMessages **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight
line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
(13 + 5) / 2 = 9 sec
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What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
a = (40 - 16) / (13 - 5) = 3 cm/s^2
a = `dv / `dt = 3cm/s^2 = (v - 16) / (9 - 5); v = 12 + 16 = 28 cm/s = (40 + 16) / 2
Because acceleration is constant, the relationship is linear and the velocity at the midpoint is just the mean of the two velocities, otherwise known as vAve
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How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
`ds = vAve * `dt = 28 * 9 = 252 cm
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By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
`dt = t_f - t_0 = 13 - 5 = 8 seconds
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By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
`dv = v_f - v_0 = 40 - 16 = 24m/s
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What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
a = `dv / `dt = 24 / 8 = 3 cm/s^2
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What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
rise = 24, equals `dv
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What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
run = 8, equals `dt
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What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
m = rise / run = `dv / `dt = a = 3
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What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Slope implies that velocity is increasing at a rate of 3cm/s change of velocity per 1 s change of clock time
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What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
a = `dv / `dt = 3cm/s^2
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*#&!
&#Very good responses. Let me know if you have questions. &#