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course PHY 241
11/17 11
An automobile traveling a straight line is at point A at clock time t = 9 sec, where it is traveling at 10 m/s, to a certain point B. If the automobile accelerates uniformly at a rate of .9 m/s/s, then if it reaches point B at clock time t = 14 sec, what is its velocity at that point? What is its average velocity over the
interval from A to B? If at point A the automobile is 44 meters from the starting point, how far is point B from the starting point?
t_A = 9 s
v_A = 10 m/s
aAve = .9 m/s^2
t_B = 14 sec
aAve = `dv / `dt = (v_B - 10) / (14 - 9) = .9
v_B - 10 = 4.5
v_B = 14.5 m/s
vAve = (v_A + v_B) / 2 = (14.5 + 10) / 2 = 12.25 m/s
s_A = 44
vAve = `ds / `dt = (s_B - 44) / 5 = 12.25
s_B - 44 = 61.25
s_B = 105.25 m from start
&#Your work looks good. Let me know if you have any questions. &#