cq_1_081

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PHY 241

Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_08.1_labelMessages **

A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.

What will be the velocity of the ball after one second?

answer/question/discussion: ->->->->->->->->->->->-> :

v_f = v_0 + a*`dt

v_f = 25 - 10(1) = 15 m/s

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What will be its velocity at the end of two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

v_f = 25 - 10(2) = 5 m/s

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During the first two seconds, what therefore is its average velocity?

answer/question/discussion: ->->->->->->->->->->->-> :

vAve = (v_f + v_0) / 2 = (25 + 5) / 2 = 15 m/s

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How far does it therefore rise in the first two seconds?

answer/question/discussion: ->->->->->->->->->->->-> :

15 m/s * 2 s = 30 m

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What will be its velocity at the end of a additional second, and at the end of one more additional second?

answer/question/discussion: ->->->->->->->->->->->-> :

v_f = 25 - 10(3) = - 5 m/s = 5 m/s downward

v_f = 25 - 10(4) = -15 m/s = 15 m/s downward

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At what instant does the ball reach its maximum height, and how high has it risen by that instant?

answer/question/discussion: ->->->->->->->->->->->-> :

v_0 = 25, v_f = 0

-10 = -25 / `dt, `dt = 2.5 s

`ds = vAve * `dt = 12.5 * 2.5 = 31.3 m

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What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?

answer/question/discussion: ->->->->->->->->->->->-> :

vAve = (25 + -15) / 2 = 5 m/s

`ds = 5 m/s * 4 s = 20 m above where it was tossed

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How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> :

v_f = 25 - 10(6) = -35 m/s

vAve = -5 m/s

`ds = -5 * 6 = -30 m = 30 m below where it was tossed

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** **

10 min

&#Very good responses. Let me know if you have questions. &#

At what clock time(s) will the ball be 20 meters above the ground?

How high will it be at the end of the sixth second?

answer/question/discussion: ->->->->->->->->->->->-> :

`ds = 8 m

v_0 = 15 m/s

a = -10 m/s^2

v_f = sqrt(15^2 + (2)(-10)(8)) = 8 m/s

-10 = -7 * `dt, `dt = 1.4 s

v_f = 15 - 10(6) = -45 m/s

vAve = -30 m/s

`ds = -30 * 6 = -180 m from initial

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