cq_1_193

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PHY 241

Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.

Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.

answer/question/discussion: ->->->->->->->->->->->-> :

Okay

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Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component

in the direction of motion or opposite to the direction of motion?

answer/question/discussion: ->->->->->->->->->->->-> :

I would perceive the component of the force along the line of motion to be forward, which would be opposite to the direction of motion

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Will the object speed up, slow down or maintain a constant speed?

answer/question/discussion: ->->->->->->->->->->->-> :

The object will slow down, because the component of teh force along the line of motion is opposite to the line of motion

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If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the

force perpendicular to the line of motion directed to the right or to the left?

answer/question/discussion: ->->->->->->->->->->->-> :

The component of the force perp to the line of motion is directed to the left

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Will the object veer to the right, to the left or maintain straight-line motion?

answer/question/discussion: ->->->->->->->->->->->-> :

The force vector has a component to the left and has no component to the right, so it will veer left

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Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?

answer/question/discussion: ->->->->->->->->->->->-> :

The force vector is 30 degrees from the line of motion and 60 degrees from perp to the line of motion, so the component parallel to the line of motion will be greater

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Very good, but if you are looking in the direction of motion the component of the force in that direction will appear to be backward.

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