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PHY 241
Your 'cq_1_21.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed vertically upward and caught at the position from which it was released.
Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> :
Acceleration is constant and total displacement is zero.
v_f^2 = v_0^2 + 2a*(0) = v_0^2
v_f = v_0
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What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> :
Is air resistance is present, the ball will not rise as far given the same initial velocity. On the way down to its original position, it will pick up less speed than
its original speed, due to air resistance slowing it down. Thus, not only will it be slower on its way up than when neglecting air resistance, but it will be even
slower on its descent
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