#$&*
mth163
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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I'm not certain that I am correctly completing the following problem:
sand pile mass:51.2g with a diameter of 4cm.
Proportionality equation between mass and diameter:
Increasing diameter increases height / depth, or volume, which is proportional to mass, and density would be constant. v=m/d. y=kx^3
Solve for K using a similar sand pile of 13cm diameter. K= Y2 / Y1 = (x2/x1)^3, Y2/51.2g = (13cm/4cm
)^3 = 1757.6g
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I have a hinch that my solution is close, but not accurate.
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@& Y2/51.2g = (13cm/4cm)^3 = 1757.6g
is simply an erroneous statement.
(13cm/4cm)^3 is not equal to 1757.6 g
However you are otherwise setting the problem up correctly, and you have the correct answer.
Y2/51.2g = (13cm/4cm)^3
is true.
It follows that
Y2= (13cm/4cm)^3 * 51.2 g = 1757.6g
It's important to write things down correctly, which helps to eliminate confusion.
In any case, good work, but be careful how you write it down.*@