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course Phy 201
6/3 10
Question: `q001 YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
The line connecting the points (7,17) to the point (10, 29) is steeper.
Rise/ run Rise/ Run
(3,5) (7,17) (7,17) (10,29)
12 / 4 = 3 12 / 3= 4
confidence rating #$&*: 3
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Self-critique Rating:OK
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Question: `q002
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Your solution:
(x - 2) * (2x + 5) (x - 2) * (2x + 5)
(2 - 2) * (4 + 5) (-2.5 - 2) * (-5 + 5)
0 * 9 = 0 -4.5 * 0 = 0
confidence rating #$&*: 3
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Question: `q002
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
(x - 2) * (2x + 5) (x - 2) * (2x + 5)
(2 - 2) * (4 + 5) (-2.5 - 2) * (-5 + 5)
0 * 9 = 0 -4.5 * 0 = 0
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Self-critique Rating:OK
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Question: `q003.
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Your solution:
3x - 6 = 0 x + 4= 0 x ^ 2 - 4 = 0
3x / 3 = 6 / 3 x = -4 sqrt x ^ 2 = sqrt 4
X = 2 x = + - 2
The solution would be zero if = 2, -2, -4
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Self-critique Rating: OK
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Question: `q004
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Your solution:
I know that the trapezoid formed from the second set of points has the greater area because it was already twice as big as the first line segment. I can see from the sketch that is does have the greater area. The second trapezoid is 40 units wide, while the first is only 4 units wide.
confidence rating #$&*:: 3
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Question: `q005
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Your solution:
Y= x ^ 2: As we move from left to right the graph increases as its slope increases
Y= 1 / x: As we move from left to right the graph decreases as its slope decreases
I used the table for y = x ^ 2
X Y
1 1
2 4
3 9
4 16
I used the table y = 1 / x
X Y
1 1
2 ½
3 1/3
4 1/4
I’m not very sure about my answers. Graphing and describing graphs are not one of my strong points.
confidence rating #$&*: 2
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Self-critique Rating: OK
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Question: `q006.
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Your solution:
20 * .1= 2 + 20 = 22
22 * .1 = 2.2 + 22 = 24.2
24.2 * .1 =2.42 + 24.2= 26.62
I couldn’t think of a strategy for calculating for 300 months but after looking at the solution I understand how you could get an answer using that strategy.
confidence rating #$&*:: 2
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Self-critique Rating: OK
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Question: `q007
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Your solution:
1 / x x= 1, .1, .01, .001
1 / 1 = 1
1 / .1= 10
1 / .01= 100
1 / .001= 1000
The values of x are approaching zero because the x values continue to grow smaller and smaller. We could continue adding zeros and following the pattern to continue approaching zero. The values of 1 / x continue to increase ten times as we continue to approach zero. The graph will continue to get steeper and steeper and grow closer to the y axis but will never touch it.
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Self-critique Rating: OK
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Question: `q008
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Your solution:
V= 3t + 90
T= clock time t= 5
V= velocity v its energy of motion is E= 800 v ^ 2
V= 3(5) + 9
V= 15 + 9
V= 24
E= 800 * 24 ^ 2
E= 800 * 576
E= 460,800
confidence rating #$&*:: 3
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Question: `q009.
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Your solution:
E = 800 * (3 * 5 + 9) ^ 2
E= 800 * (24) ^ 2
E= 800 * 576
E= 460,800
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Self-critique Rating: OK
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Question: `q010
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Your solution:
(2 ^ x - 1) (x ^ 2 - 25) (2x + 6)
2 ^ x - 1 = 0 x ^ 2 - 25 = 0 2x + 6 = 0
2 ^ x = 1 x ^ 2 = 25 2x = 6
X= 0 sqrt x ^ 2 = sqrt 25 2x / 2 = 6 / 2
X= + - 5 x= 3
confidence rating #$&*: 2
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Question: `q011
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Your solution:
The second points form a trapezoid with a greater area, although all four points have the same run, the second set of points have a greater rise by 2 units.
confidence rating #$&*:: 3
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Question: `q012
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Your solution:
1000 * .1 + 1000= 1100
1100 * .1 + 1100= 1210
1210 * .1 + 1210= 1331
1000 * 1.1 ^ 40
1000 * 1.1 ^ t
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Self-critique Rating: OK
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Good responses. I'll leave it up to you whether you want to resubmit this. Your responses could very nearly stand on their own as a reference document.
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