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course mth 152
9/15 11
question 11.2.12 find 10! / [ 4! (10-4)! ] without calculator
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Your Solution:
5 * 3 * 2 * 7 = 210
3
Ok
question 11.2.31 (10th edition #25) 3 switches in a row; fund count prin to find # of possible settings
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Your Solution:
2 * 2 * 2 = 8 possible setting for the three switches
2
Ok
question 11.2.31 (10th edition #27) If no two adjacent switches are off why does the fundamental counting principle not apply?
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Your Solution:
The choices are not independent therefore the rule does not apply
3
Ok
question 11.2.36 How many odd 3-digit #'s from the set {3, 4, 5}?
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Your Solution:
3*3*2=18 possible combinations
3
Ok
question 11.2.56 (10th edition 50) 10 guitars, 4 cases, 6 amps, 3 processors; # possible setups
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Your Solution:
10 * 4 * 6 * 3 = 720 possible setups
2
Ok
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