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phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 4 cm/s + 10 cm/s = 14 cm/s / 2 =
7 cm/s is the average speed.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): This is just a guess because I do not have the amount of time the ball rolled to accurately calculate the average speed.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): The ball probably traveled between 12 cm and 30 cm.
I calculated the distance for each given velocity in 3 seconds.
If the ball was going at 4 cm/s, it would cover 12 cm in 3 seconds and if the ball was going at 10 cm/s, it would cover 30 cm in 3 seconds.
@& Good. What single displacement do you therefore think answers the question?*@
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): Average rate = change in velocity / change in time
Average rate = 6 cm/sec / 3 sec = 2 cm/sec/sec
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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