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phy 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> :
The pendulum would take 1 second to get from one extreme point to the other, 1/2 second to get from an extreme point to equilibrium, and 1 1/2 seconds to go from one extreme point to equilibrium to extreme and back to equilibrium.
What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> :
I arrived at my answer by assuming that the pendulum's swing is constant throughout it's cycle. The pendulum takes 2 seconds to go through a complete cycle. That cycle is made up of 4 parts, extreme to equilibrium, equilibrium to opposite extreme, opposite extreme to equilibrium, and from equilibrium back to original extreme. 2 seconds divided by 4 is 1/2. I assumed that each part of the cycle takes 1/2 seconds to complete.
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15 minutes
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&#Your work looks very good. Let me know if you have any questions. &#