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phys 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
1st automobile:
Ds = v0 * dt + .5a * dt2
Ds = 10 m
Dt = 8s
V0 = 0 m/s
Slope = .05
10m = .5 (a) * 82
10 m = 32 (a)
A = .3125 m/s/s
.3125 m/s/s / .05 = 6.25 m/s/s
2nd automobile
Ds = v0 * dt + .5a * dt2
Ds = 10 m
Dt = 5 s
V0 = 0 m/s
Slope = .1
10 m = .5 (a) * 25
10 m = 12.5 (a)
A = .8 m/s/s / .1 = 8 m/s/s
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&#Very good responses. Let me know if you have questions. &#