course Mth 152 I may have already sent this to you. I lost internet connection while it was submitting the assignment to you and I wasn't sure that you got it. {\܁i㼀D۵assignment #020
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19:38:44 query 9.1.36 Ray MO U ray OM **** How do you express the intersection of the two rays?
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RESPONSE --> Line MO or Line OM
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19:39:53 ** STUDENT SOLUTION: The intersection of the two rays consists of the elements common to both sets, which would be MO. However, a union symbol is used in the question and a union is composed of all the elements found in atleast one of the two sets, which would also be MO. **
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RESPONSE --> I put line MO and line OM. Is that the same?
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19:47:03 **** query 9.1.54 lines SR and TP intersecting at Q **** What are the names of the pairs of vertical angles for this figure?
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RESPONSE --> angle SQT and PQR angle SQP and TQR
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19:47:23 ** STUDENT SOLUTION: The vertical angles are SQT and PQR; SQP and TQR **
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RESPONSE --> That is what I got
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19:50:37 **** query 9.1.60 5x - 129 vert with 2x - 1 **** What is the value of x and how did you obtain it?
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RESPONSE --> 5x - 129 = 2x - 21 3x = 108 x = 36
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19:50:58 *&*& Starting with 5x - 129 = 2x - 21 to get 3x - 129 = -21. Add 129 to both sides to get 3x = 108. Divide both sides by 3 to get x = 36. To check substitute 36 in for x in the equation and simplify, getting 51 = 51.
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RESPONSE --> I sub. the 36 in and got 51 = 51 also.
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19:58:08 **** What equation did you solve to obtain x, and how did you get the equation?
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RESPONSE --> vertical angles have equal measurements worked it as equal to each other
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19:58:31 Since the angles are vertical angles, they are equal to eachother, therefore, I set them up to be equal to eachother and then solved.To check myself, I then substituted my answer in for x on both sides of the equation to make sure they were equal.
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RESPONSE --> That is kinda what I said.
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20:05:53 **** query 9.1.72 complement 10 deg less that 1/5 of suppl **** What is the measure of the angle and how did you get it?
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RESPONSE --> 180 - x = 10 + .2(90-x) 180 - x = 10 + 18 - .2x 180 - x = 28 - .2x 152 - x = .2x 152 = .8x x = 190
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20:08:36 ** Let x be the degree measure of the angle. Then the supplement is 180 x; 10 deg less than 1/5 the supplement is 1/5(180 - x) 10. The complement is 90 - x. So the equation is 90 - x = 1/5(180 - x) 10. Multiplying both sides by 5 we get 450 5 x = 180 x 50 so that 450 5 x = 130 x. Adding x 450 to both sides we get -4x = -320 so thatx = 80. The complement of 80 deg is 10 deg. The supplement of 80 deg is 100 deg; 1/5 the supplement is 1/5 * 100 deg = 20 deg, so the complement 10 deg is 10 deg less than the supplement 20 deg. **
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RESPONSE --> I worked it as a supplement angle. But I see what I did wrong and see why it make such a difference
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20:09:07 **** What equation did you solve to obtain the measure of the angle?
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RESPONSE --> I used the supplement equation and it should habve been complement instead
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20:09:27 Student Response: I determined which equations represented the degree measure of the angle, complement, and supplement. I then substituted those in the equation using the worded problem. 90 - x (complement) = 10 (10 less than) - 1/5 (1/5 of the supplement) 180 - x (supplement).
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RESPONSE --> I see what I did wrong.
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20:09:40 **** Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE -->
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20:09:45 The query was basically what I expected it to be.
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RESPONSE -->
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