cq_1_192

Phy 231

Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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Sketch a vector representing a 10 Newton force which acts vertically downward.

• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.

answer/question/discussion: ->->->->->->->->->->->-> :

By doing this it gives you a 70 reference angle in the 3rd quadrant which after roating gives you a 20 degree x above and 20 degree left of y axis.

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• What are the x and y components of the equilibrant of the force?

answer/question/discussion: ->->->->->->->->->->->-> :

10cos(250) =- 3.4 N

10sin(250) = -9.4 N

So it would be x=3.4N approx and y=9.4N approx

#$&*

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10mins

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7/9 7:50

&#Your work looks very good. Let me know if you have any questions. &#