Phy 231
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
By doing this it gives you a 70 reference angle in the 3rd quadrant which after roating gives you a 20 degree x above and 20 degree left of y axis.
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
10cos(250) =- 3.4 N
10sin(250) = -9.4 N
So it would be x=3.4N approx and y=9.4N approx
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10mins
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7/9 7:50
Your work looks very good. Let me know if you have any questions.