cq_1_242

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Phy 231

Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.

• Is the total momentum of the system after collision the same as the total momentum before?

answer/question/discussion: ->->->->->->->->->->->-> :

.06kg*.8m/s=.048kg m/s

(.06kg*.5m/s)+(.02kg*.7m/s)=.044kg m/s

No more momentum before collision

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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?

answer/question/discussion: ->->->->->->->->->->->-> :

.018/.02=.9

.9m/s to keep momentum same of the marble

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10 mins

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7/23 12:35

&#Good responses. Let me know if you have questions. &#