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course Phy 231
7/24 10:30
4, 10, .013J, .00012J, .013J, .0052J 4, 20, .025J, .00024J, .023J, .0092J
4, 30, .037J, .00036J, .035J, .014J
This is the 3 trials to the right off the ledge, 4 dominos, followed by distance in cm, PE lost, frictional, translational KE, and rotational KE.
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The work against friction I found by the .0012N and multiplied it by the distance of the ramp in meters that the ball rolled. Which is in the middle column above. .0012N*.1m=.00012J loss to friction is line 1.
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looks good except for the work done against friction, which will be modified.
This should modify some of the results in your last insertion
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I now took 2.432cm/s^2 loss in acceleration and .1kg of the ball
.1kg*.02432m/s^2=.0024N approx divide that by 2 for friction up and down the ramp .0012N approx.
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GOod. This affects one of the columns of your table (work done against friction). It should just take you a couple of minutes to modify those three quantities, document how you've changed them by giving a sample calculation of work against friction, and resubmit.
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&#Very good responses. Let me know if you have questions. &#
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