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course PHY201
9-12-10 12:15am
Determine the acceleration of an object whose velocity is initially 15 cm/s and which accelerates uniformly through a distance of 51 cm in 4.1 seconds.v0=15
'dt=4
'ds=51
using the formula 'ds=v0'dt+.5a'dt^2
a=('ds-v0'dt)/.5'dt^2
a=(51-15*4)/.5(4)^2
a=-9/8
a=1.125cm/s^2"
&#Very good work. Let me know if you have questions. &#