#$&*
PHY201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
v0=0
a='ds-(v0(dt))/.5dt^2
a=10-(0*8)/.5(8^2)
a=10/32
a=.31m/s^2
a=10/.5(5^2)
a=.8m/s^2
#$&*
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15 minutes
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Did I get this right?
Your accelerations are good. You didn't calculate the rate of change of accel. with respect to ramp slope. Try to figure out what that means and how you would calculate it, before you go to the link below.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#