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Phy 231
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
a = (vf – v0) / dt
a = acceleration; vf = final velocity; v0 = initial velocity; dt = change in time
a = 8 cm/s^2
vf = ?
v0 = 12 cm/s
dt = 3 s
vf = [(a)*(dt)] + v0
vf = [(8 cm/s^2)*(3 s)] + 12 cm/s = 24 cm/s + 12 cm/s = 36 cm/s
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
When acceleration is constant:
vAve = (v0 + vf) / 2
vAve = average velocity; v0 = initial velocity; vf = final velocity
vAve = ?
v0 = 12 cm/s
vf = 36 cm/s
vAve = (12 cm/s + 36 cm/s) / 2 = (48 cm/s) / 2 = 24 cm/s
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = ds / dt
vAve = average velocity; ds = change in position; dt = change in time
vAve = 24 cm/s
ds = ?
dt = 3 s
ds = (vAve)*(dt)
ds = (24 cm/s)*(3 s) = 72 cm
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15 min
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&#This looks very good. Let me know if you have any questions. &#