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Phy 231
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
• A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
v0, vf, and ds are given
v0 = 10 cm/s
vf = 20 cm/s
ds = 45 cm
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• A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
a, dt, vf are given
a = 10 cm/s^2
dt = 3 seconds
vf = 50 cm/s
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• A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
ds, v0, a are given
ds = 30 cm
v0 = 0
a = 20 cm/s^2
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Then for each situation answer the following:
• Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = (v0 + vf) / 2 when uniform acceleration and vAve = ds / dt
When v0, vf, and ds are given:
Yes it is possible because vAve = (v0 + vf) / 2 and you are give v0 and vf
When a, dt, vf are given
Yes it is possible because a = (vf – v0) / `dt. Solving for v0 we get
v0 = vf - [(a)*(`dt)]. You are given vf, a, and dt. Then once you solve for the v0 you can solve for vAve = (v0 + vf) / 2.
When ds, v0, a are given
No it is not possible because in order to find the vAve you need to have `dt.
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• Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> :
When v0, vf, and ds are given
Yes it is possible because `dv = vf – v0 and you are given both vf and v0
When a, dt, vf are given
Yes it is possible because a = `dv / `dt and therefore `dv = (a)*(`dt) and you are given both a and `dt.
When ds, v0, a are given
No it is not possible because you will either need to be given vf or `dt in order to find `dv.
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15 min
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This looks very good. Let me know if you have any questions.