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Phy 231
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: ->->->->->->->->->->->-> :
It takes 1 second to get from one extreme point to the other. It takes 0.5 seconds to get from extreme point to equilibrium. It takes 1.5 seconds to go from extreme point to equilibrium to opposite extreme point and back to equilibrium.
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• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: ->->->->->->->->->->->-> :
I assumed that acceleration remained constant throughout the cycle and that the amplitude was independent from the time required for a cycle.
The pendulum speeds up sometimes, slows down sometime, and also passes through an instant of transition between speeding up and slowing down (at which instant the acceleration is zero). So acceleration can't be constant.
However if the rhythm is constant, and if each quarter-cycle takes the same time as every other, then your conclusion follows.
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About 5 minutes
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&#Good responses. See my notes and let me know if you have questions. &#