phy 201
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: I sketched the graph.
• Sketch a straight line segment between these points.
answer/question/discussion: the graph has a positive slope
• What are the rise, run and slope of this segment?
answer/question/discussion: rise is 40cm/s-10cm/s=30cm/s; run is 9s-4s=5s; slope is 30cm/s/5s=6cm/s^2 I’m unsure of my units on the slope. It makes since to me now, but then, it’s 1AM
your units are right
• What is the area of the graph beneath this segment?
answer/question/discussion: I took the areas of the triangle that was formed by the line and the graph’s rise and run, and the area of the rectangle underneath, and added them together.
Area of tri:1/2(5s*30cm/s)=75cm/s^2 area of rec: 5s*10cm/s=50cm/s^2 75+50=125 cm/s^2 once again, I’m unsure about the units, here.
s * cm/s = cm
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20-30 minutes
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No need for a revision, but check my notes and the link below:
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#