Test Help

course Mth 173

I tried to open up the other form about the test that you sent me back and it was empty so I'm going to ask you again how do you want me to take it on the computer. Can I do it at home if I promise that I will not cheat? I will use this form to sumit it. If you are wondering why it took me so long to get back to you my computer has been down.

Any arrangment I make for one student would have to be available to all students, and while I might well be willing to accept your word, I could not do that for all my students. So the test needs to be taken in a proctored situation.

I've emailed the library to ask if it would be possible for you to complete your test using a keyboard. I'll let you know when I get a response.

The velocity of the object is changing on the graph and is represented by the line. When the average of this changing velocity is taken, it is the center of that appointed line. This center is always the center of the base of the trapezoid that it forms. This gives us the midpoint clock time.

* Is a graph of average velocity vs. midpoint clock time linear, or nearly so?

The graph will be linear since the vAve will always be at the tmid.

* Does the velocity of the water surface seem to change at an approximately constant rate?

No. It appears that the velocity of the water leaving the cylinder is decreasing.

* Could this be a uniform-acceleration situation?

I do not believe this could be a uniform-acceleration situation since the v vs. t graph would not be linear: it would be parabolic."

Good answers to the questions. Let me know if you have questions.