PHY 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: ->->->->->->->->->->->-> :
If the pendulum requires 2 seconds to complete a cycle, then it would take approximately 1 second to go from one extreme point to the other. If it takes 1 second to go from one extreme point to the other, then it would take approximately ½ second to get from extreme point to equilibrium. If its take 1 second to go from on extreme point to the other and ½ second to get from extreme point to equilibrium, then it would take 1 ½ seconds to go from one extreme to the other and back to equilibrium.
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• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: ->->->->->->->->->->->-> :
If it took 2 seconds to complete the whole cycle, then I just divided it up into sections or parts of the pendulum, by just subtracting the 2 seconds from 1 second, and then you have a half of a cycle. Then you just divide 1 second into 2, which gives you .5 second that is a quarter of a cycle.
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30 minutes
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June 25 around 9:40 am
&#Very good responses. Let me know if you have questions. &#