Assignment 2 qa

course Mth 271

7/3 12:45

Question: `q001. Recall the stock value problem, where March, July and December values were $5000, $5300 and $5500. Construct a graph of stock value vs. number of month (e.g., 1 for Jan, 2 for Feb, etc.). You will have three points on your graph, one corresponding to the March value, one to the July value, and one to the December value. Stock value will be on the y axis and month number on the x axis. Your first point, for example, will be (3, 5000), corresponding to $5000 in March.

Connect your three points with straight lines--i.e., connect the first point to the second and the second to the third.

What is the slope of your line between the first and second point, and what is the slope of your line between the second in the third point? Recall that slope is rise / run.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The three points that were given are (3, 5000), (7, 5300), (12, 5500). To find the slope of the two lines, I used change in stock/change in time. For the first line I used the values 300/4 to get a slope of 75 (which represents the average rate of change of $75 per month). For the second line I used the values 200/5 to obtain a slope of 40 (which represents the average rate of change of $40 per month).

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about this problem.

.............................................

Given Solution:

`aThe three points on the graph are (3, 5000), (7, 5300) and (12, 5500).

The rise between the first point and the second is from 5000 to 5300, or 300, and the run is from 3 to 7, or 4, so the slope is 300 / 4 = 75. Note that the 300 represents $300 and the 4 represents 4 months, so the slope represents $300 / (4 months) = $75 / month, which is the average rate of change during the first time interval.

The rise between the second point and the third is from 5300 to 5500, or 200, and the run from 7 to 12 is 5, so the slope is 200 / 5 = 40. This slope represents the $40/month average rate of change during the second time interval. Click on 'Next Picture' to see the graph.

`routine graph2

Self-critique Rating:

By using the equation given during the cylinder lecture (change in depth/change in time) and modifying it to fit this equation, I was able to obtain the values for slope.

*********************************************

Question: `q002. Look at your results for the slopes, and look the results for the average rates of change. What do you notice? In what way then does the graph represent the average rate of change?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

I notice that the graphs are the same. Slope represents the average rate of change in that it is increasing each month at the given rate (slope).

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel confident about this problem.

.............................................

Given Solution:

`aWe see from this example that the slope of a graph of value vs. clock time represents the rate at which value is changing with respect to clock time.

Self-critique Rating:

I used logic to answer this question.

*********************************************

Question: `q003. To what extent do you think your graph, consisting of 3 points with straight line segments between them, accurately depicts the detailed behavior of the stocks over the 9-month period?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

I doubt that this graph is very accurate. Stocks change on a daily basis and it is more likely that this graph shows a general trend.

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about my answer.

.............................................

Given Solution:

`aStocks can do just about anything from day to day-they can go up or down more in a single day than their net change in a month or even a year. So based on the values several months apart we can't say anything about what happens from day to day or even from month to month. We can only say that on the average, from one time to another, the stocks changed at a certain rate.

Self-critique Rating:

I used logic and knowledge about the stock market to answer this question.

*********************************************

Question: `q004. From the given information, do you think you can accurately infer the detailed behavior of the stock values over the nine-month period?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

No, I can only determine the general trend from this nine month period.

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about this problem.

.............................................

Given Solution:

`aNot on a day-to-day basis, and not even on a month-to-month basis. All we can see from the given information is what might be an average trend.

&#Your work looks good. Let me know if you have any questions. &#

Assignment 2 qa

course Mth 271

7/3 12:45

Question: `q001. Recall the stock value problem, where March, July and December values were $5000, $5300 and $5500. Construct a graph of stock value vs. number of month (e.g., 1 for Jan, 2 for Feb, etc.). You will have three points on your graph, one corresponding to the March value, one to the July value, and one to the December value. Stock value will be on the y axis and month number on the x axis. Your first point, for example, will be (3, 5000), corresponding to $5000 in March.

Connect your three points with straight lines--i.e., connect the first point to the second and the second to the third.

What is the slope of your line between the first and second point, and what is the slope of your line between the second in the third point? Recall that slope is rise / run.

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The three points that were given are (3, 5000), (7, 5300), (12, 5500). To find the slope of the two lines, I used change in stock/change in time. For the first line I used the values 300/4 to get a slope of 75 (which represents the average rate of change of $75 per month). For the second line I used the values 200/5 to obtain a slope of 40 (which represents the average rate of change of $40 per month).

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about this problem.

.............................................

Given Solution:

`aThe three points on the graph are (3, 5000), (7, 5300) and (12, 5500).

The rise between the first point and the second is from 5000 to 5300, or 300, and the run is from 3 to 7, or 4, so the slope is 300 / 4 = 75. Note that the 300 represents $300 and the 4 represents 4 months, so the slope represents $300 / (4 months) = $75 / month, which is the average rate of change during the first time interval.

The rise between the second point and the third is from 5300 to 5500, or 200, and the run from 7 to 12 is 5, so the slope is 200 / 5 = 40. This slope represents the $40/month average rate of change during the second time interval. Click on 'Next Picture' to see the graph.

`routine graph2

Self-critique Rating:

By using the equation given during the cylinder lecture (change in depth/change in time) and modifying it to fit this equation, I was able to obtain the values for slope.

*********************************************

Question: `q002. Look at your results for the slopes, and look the results for the average rates of change. What do you notice? In what way then does the graph represent the average rate of change?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

I notice that the graphs are the same. Slope represents the average rate of change in that it is increasing each month at the given rate (slope).

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel confident about this problem.

.............................................

Given Solution:

`aWe see from this example that the slope of a graph of value vs. clock time represents the rate at which value is changing with respect to clock time.

Self-critique Rating:

I used logic to answer this question.

*********************************************

Question: `q003. To what extent do you think your graph, consisting of 3 points with straight line segments between them, accurately depicts the detailed behavior of the stocks over the 9-month period?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

I doubt that this graph is very accurate. Stocks change on a daily basis and it is more likely that this graph shows a general trend.

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about my answer.

.............................................

Given Solution:

`aStocks can do just about anything from day to day-they can go up or down more in a single day than their net change in a month or even a year. So based on the values several months apart we can't say anything about what happens from day to day or even from month to month. We can only say that on the average, from one time to another, the stocks changed at a certain rate.

Self-critique Rating:

I used logic and knowledge about the stock market to answer this question.

*********************************************

Question: `q004. From the given information, do you think you can accurately infer the detailed behavior of the stock values over the nine-month period?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

No, I can only determine the general trend from this nine month period.

Confidence rating:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

I feel very confident about this problem.

.............................................

Given Solution:

`aNot on a day-to-day basis, and not even on a month-to-month basis. All we can see from the given information is what might be an average trend.

&#Your work looks good. Let me know if you have any questions. &#