21 Open Queries

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course PHY 201

10/26 10 amIf your solution to stated problem does not match the given solution, you should self-critique per instructions at http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

If your solution to stated problem does not match the given solution, you should self-critique per instructions at http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

021. `query 21

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Question: `q Explain how to obtain the final speed and direction of motion of a projectile which starts with known velocity in the horizontal direction and falls a known vertical distance, using the analysis of vertical and horizontal motion and vectors.

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Your solution:

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Horizontal speed will not change. V0 vertical =0 and knowing that a=9.8 m/s^2, we can use the equations of motion to solve for Vf. Knowing the horizontal and vertical components of velocity, we can use the Pythagorean theorem to solve for the magnitude of the vector and use arc tan to solve for direction.

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confidence rating #$&*:

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Given Solution:

`a** The horizontal velocity is unchanging so the horizontal component is always equal to the known initial horizontal velocity.

The vertical velocity starts at 0, with acceleration thru a known distance at 9.8 m/s^2 downward. The final vertical velocity is easily found using the fourth equation of motion.

We therefore know the x (horizontal) and y (vertical) components of the velocity. Using the Pythagorean Theorem and arctan (vy / vx) we find the speed and direction of the motion. **

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Self-critique (if necessary):

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self-critique rating #$&*:

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Question: `qGive at least three examples of vector quantities for which we might wish to find the components from magnitude and direction. Explain the meaning of the magnitude and the direction of each, and explain the meaning of the vector components.

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Your solution:

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a car on a ramp. The magnitude would be the velocity of the car and the direction would be the way the car is traveling.

A ball on a ramp. The magnitude would be the velocity and the direction would be the way the ball is moving.

A force of some sort. The magnitude would be the force and the direction would be the way the force is acting.

The vector components would be the x/y components. Using them to find the resultant, it would tell the magnitude and direction as well.

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confidence rating #$&*:

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Given Solution:

Examples might include:

A force acting on an object causing it to move in an angular direction.

A ball falling to the ground with a certain velocity and angle.

A two car collision; velocity and momentum are both vector quantities and both important for analyzing the collision..

The magnitude and directiohn of the relsultant is the velocity and direction of travel.

The vector components are the horizontal and vertical components that would produce the same effect as the resultant.

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Self-critique (if necessary):

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self-critique rating #$&*:

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&#Your work looks very good. Let me know if you have any questions. &#

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