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PHY 201
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_06.1_labelMessages **
For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> scussion:
initial velocity, final velocity, and change in displacement are given:
v0= 10cm/s
vf = 20cm/s
`ds= 45cm
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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> scussion:
acceleration, change in clock time, and final velocity are given:
a= 10 cm/s^2
`dt = 3 sec
vf= 50cm/s
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A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Total displacement, initial velocity, and acceleration are given:
`ds= 30cm
v0= 0cm/s
a= 20cm/s^2
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Then for each situation answer the following:
Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
vAve= `ds / `dt OR vAve= v0 + vf /2
The first situation gives v0 and vf so yes, it is possible using the second method.
The second situation gives vf and `dt, but not directly v0 or `ds. v0 could be figured by taking aAve = `dv /`dt and solving for `dv. Since vf is known, v0= `dv - vf.
The third situation gives `ds, a, and v0, so using the same method as previously stated, it would be possible to find `dt and vf.
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Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
`dv could be found in situation one and two relatively easily. For the third situation, we would use vf^2= v0^2 + 2a`ds and solve for vf. Once vf is found we could reason `dv by subtracting v0 from vf.
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20min
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&#Your work looks very good. Let me know if you have any questions. &#